Derivative sin with respect to cos (dsin(x)/dcos(x)) using tiny nudges

Yes, let's find dsin/dcos using tiny little nudges. Note : I used theta instead of x inspired by: 3blue1brown's tiny nudges : https://www.youtube.com/watch?v=S0_qX4VJhMQ, https://odysee.com/@3Blue1Brown:b/derivative-formulas-through-geometry flammable maths's dsin/dcos : https://www.youtube.com/watch?v=zrgS56vZ_Co&t=129s