Improper Integrals Example 5: 1/sqrt(x-2)

In this video I go over another example on improper integrals and this time solve the integral of the function 1/sqrt(x-2) from x =2 to x = 5. This integral is a Type 2 improper integral because the integrand has an infinite discontinuity or vertical asymptote at x = 2. But when we write this integral as a limit of a definite integral, the limit ends up converging to the value 2*sqrt(3) and thus represents the area under the curve.

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Related Videos:

Improper Integrals: Type 2: Discontinuous Integrands: https://youtu.be/livlGUBuM54 Improper Integrals: Introduction: https://youtu.be/ud44W-0jC-c The Definite Integral - Brief Introduction: http://youtu.be/vhMP5SKbQjU Integrals and Areas Between Curves: http://youtu.be/2F03KMLIzbk Infinite Limits - Precise Definition: http://youtu.be/QyVTgSzn7dE Infinite Limits - Vertical Asymptotes: http://youtu.be/H-5Txa8SOwQ .

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