Improper Integrals Example 4: 1/x^p

In this video I go over another example on improper integrals and this time solve for the values of p in the integral 1/x^p from x = 1 to x approaches infinite, that make this integral convergent. Please note that in the Example 1 of the example video series, see video link below, I have already showed that for the case of p = 1, the integral diverges. In this example I show that the integral converges to 1/(p - 1) for p is greater than 1 but diverges for p is less than 1.

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Related Videos:

Improper Integrals: Example 3: 1/(1+x^2): https://youtu.be/6KizcIQ6H_E Improper Integrals: Example 2: x*e^x: https://youtu.be/w2FxwExbBac Improper Integrals: Example 1: Divergent Sum: https://youtu.be/6b_zaerpudo Improper Integrals: Introduction: https://youtu.be/ud44W-0jC-c Improper Integrals: Type 1: Infinite Intervals: https://youtu.be/9ZlsCy3wdZU Infinite Limits - Precise Definition: http://youtu.be/QyVTgSzn7dE Infinite Limits - Vertical Asymptotes: http://youtu.be/H-5Txa8SOwQ Derivative of y = x^n - Part 2: General Power Rule: http://youtu.be/Ibvu33oh49o .

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