Chord which are equidistant from the center of circle are equal.

Circle Theorem: Chord which are equidistant from the center of circle are equal.

Equal chords of a circle are equidistant from the center: https://youtu.be/ZPrc0_v7u-Y

---~~~--- Please watch: "If 𝒙^𝒂.𝒙^𝒃=(𝒙^𝒂 )^𝒃, show that 𝒂/𝒃+𝒃/𝒂=𝒂𝒃−𝟐." https://www.youtube.com/watch?v=rZcUcisuYSc ---~~~--- Follow us: Facebook: https://facebook.com/mathswitharjun Twitter: https://twitter.com/twitajr ... https://www.youtube.com/watch?v=-dWCC4MY9OM